11304114047131 has 2 divisors, whose sum is σ = 11304114047132. Its totient is φ = 11304114047130.

The previous prime is 11304114047123. The next prime is 11304114047137. The reversal of 11304114047131 is 13174041140311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11304114047131 - 2³ = 11304114047123 is a prime.

It is a super-3 number, since 3×11304114047131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 11304114047093 and 11304114047102.

It is not a weakly prime, because it can be changed into another prime (11304114047137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652057023565 + 5652057023566.

It is an arithmetic number, because the mean of its divisors is an integer number (5652057023566).

Almost surely, 2^{11304114047131} is an apocalyptic number.

11304114047131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11304114047131 is an equidigital number, since it uses as much as digits as its factorization.

11304114047131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 31.

Adding to 11304114047131 its reverse (13174041140311), we get a palindrome (24478155187442).

The spelling of 11304114047131 in words is "eleven trillion, three hundred four billion, one hundred fourteen million, forty-seven thousand, one hundred thirty-one".