Base | Representation |
---|---|
bin | 10000011100110011000… |
… | …001000000100100010111 |
3 | 11000001211202210212001102 |
4 | 100130303001000210113 |
5 | 122010111132120320 |
6 | 2223151411220315 |
7 | 144446111010101 |
oct | 20346301004427 |
9 | 4001752725042 |
10 | 1130432301335 |
11 | 3a6460622457 |
12 | 1631035a769b |
13 | 827a38b127c |
14 | 3c9db0c4571 |
15 | 1e61251e175 |
hex | 10733040917 |
1130432301335 has 24 divisors (see below), whose sum is σ = 1368404016000. Its totient is φ = 896473061568.
The previous prime is 1130432301329. The next prime is 1130432301403. The reversal of 1130432301335 is 5331032340311.
It is not a de Polignac number, because 1130432301335 - 210 = 1130432300311 is a prime.
It is a super-3 number, since 3×11304323013353 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1130432301298 and 1130432301307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 63681041 + ... + 63698789.
It is an arithmetic number, because the mean of its divisors is an integer number (57016834000).
Almost surely, 21130432301335 is an apocalyptic number.
1130432301335 is a deficient number, since it is larger than the sum of its proper divisors (237971714665).
1130432301335 is an equidigital number, since it uses as much as digits as its factorization.
1130432301335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18455 (or 18216 counting only the distinct ones).
The product of its (nonzero) digits is 9720, while the sum is 29.
Adding to 1130432301335 its reverse (5331032340311), we get a palindrome (6461464641646).
The spelling of 1130432301335 in words is "one trillion, one hundred thirty billion, four hundred thirty-two million, three hundred one thousand, three hundred thirty-five".
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