11304331307 has 2 divisors, whose sum is σ = 11304331308. Its totient is φ = 11304331306.

The previous prime is 11304331273. The next prime is 11304331343. The reversal of 11304331307 is 70313340311.

It is a weak prime.

It is an emirp because it is prime and its reverse (70313340311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11304331307 is a prime.

It is a super-3 number, since 3×11304331307³ (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11304331397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652165653 + 5652165654.

It is an arithmetic number, because the mean of its divisors is an integer number (5652165654).

Almost surely, 2^11304331307 is an apocalyptic number.

11304331307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11304331307 is an equidigital number, since it uses as much as digits as its factorization.

11304331307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268, while the sum is 26.

Adding to 11304331307 its reverse (70313340311), we get a palindrome (81617671618).

The spelling of 11304331307 in words is "eleven billion, three hundred four million, three hundred thirty-one thousand, three hundred seven".