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113044003 is a prime number
BaseRepresentation
bin1101011110011…
…10101000100011
321212201020012221
412233032220203
5212414402003
615114531511
72541600232
oct657165043
9255636187
10113044003
11588a06a6
1231a36b97
131a55ca57
1411028b19
159dce7bd
hex6bcea23

113044003 has 2 divisors, whose sum is σ = 113044004. Its totient is φ = 113044002.

The previous prime is 113043989. The next prime is 113044007. The reversal of 113044003 is 300440311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113044003 - 25 = 113043971 is a prime.

It is a super-3 number, since 3×1130440033 (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (113044007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56522001 + 56522002.

It is an arithmetic number, because the mean of its divisors is an integer number (56522002).

Almost surely, 2113044003 is an apocalyptic number.

113044003 is a deficient number, since it is larger than the sum of its proper divisors (1).

113044003 is an equidigital number, since it uses as much as digits as its factorization.

113044003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 113044003 is about 10632.2153383009. The cubic root of 113044003 is about 483.5215586621.

Adding to 113044003 its reverse (300440311), we get a palindrome (413484314).

The spelling of 113044003 in words is "one hundred thirteen million, forty-four thousand, three".