11305012251031 has 4 divisors (see below), whose sum is σ = 11305050975792. Its totient is φ = 11304973526272.

The previous prime is 11305012250981. The next prime is 11305012251037. The reversal of 11305012251031 is 13015221050311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11305012251031 - 2¹¹ = 11305012248983 is a prime.

It is a super-2 number, since 2×11305012251031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11305012250987 and 11305012251005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11305012251037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18921130 + ... + 19509463.

It is an arithmetic number, because the mean of its divisors is an integer number (2826262743948).

Almost surely, 2^{11305012251031} is an apocalyptic number.

11305012251031 is a deficient number, since it is larger than the sum of its proper divisors (38724761).

11305012251031 is an equidigital number, since it uses as much as digits as its factorization.

11305012251031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38724760.

The product of its (nonzero) digits is 900, while the sum is 25.

The spelling of 11305012251031 in words is "eleven trillion, three hundred five billion, twelve million, two hundred fifty-one thousand, thirty-one".