Base | Representation |
---|---|
bin | 10000011100110111010… |
… | …100111100010010001011 |
3 | 11000002000210220210220201 |
4 | 100130313110330102023 |
5 | 122010233141314111 |
6 | 2223202513433031 |
7 | 144450646565005 |
oct | 20346724742213 |
9 | 4002023823821 |
10 | 1130504635531 |
11 | 3a6498438187 |
12 | 16312386b777 |
13 | 827b588937b |
14 | 3ca06953375 |
15 | 1e618a5b6c1 |
hex | 1073753c48b |
1130504635531 has 2 divisors, whose sum is σ = 1130504635532. Its totient is φ = 1130504635530.
The previous prime is 1130504635493. The next prime is 1130504635541. The reversal of 1130504635531 is 1355364050311.
It is a strong prime.
It is an emirp because it is prime and its reverse (1355364050311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1130504635531 - 223 = 1130496246923 is a prime.
It is a super-2 number, since 2×11305046355312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1130504635541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565252317765 + 565252317766.
It is an arithmetic number, because the mean of its divisors is an integer number (565252317766).
Almost surely, 21130504635531 is an apocalyptic number.
1130504635531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130504635531 is an equidigital number, since it uses as much as digits as its factorization.
1130504635531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 1130504635531 its reverse (1355364050311), we get a palindrome (2485868685842).
The spelling of 1130504635531 in words is "one trillion, one hundred thirty billion, five hundred four million, six hundred thirty-five thousand, five hundred thirty-one".
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