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1130544354553 is a prime number
BaseRepresentation
bin10000011100111001101…
…100011101010011111001
311000002010120122202011121
4100130321230131103321
5122010323323321203
62223210453025241
7144451641312625
oct20347154352371
94002116582147
101130544354553
113a65088a6719
12163135025221
13827c0b85053
143ca0bd32185
151e61c2a50bd
hex10739b1d4f9

1130544354553 has 2 divisors, whose sum is σ = 1130544354554. Its totient is φ = 1130544354552.

The previous prime is 1130544354517. The next prime is 1130544354601. The reversal of 1130544354553 is 3554534450311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 807774930169 + 322769424384 = 898763^2 + 568128^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1130544354553 is a prime.

It is a super-2 number, since 2×11305443545532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1130544354503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565272177276 + 565272177277.

It is an arithmetic number, because the mean of its divisors is an integer number (565272177277).

Almost surely, 21130544354553 is an apocalyptic number.

It is an amenable number.

1130544354553 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130544354553 is an equidigital number, since it uses as much as digits as its factorization.

1130544354553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080000, while the sum is 43.

The spelling of 1130544354553 in words is "one trillion, one hundred thirty billion, five hundred forty-four million, three hundred fifty-four thousand, five hundred fifty-three".