Base | Representation |
---|---|
bin | 110100101001010011… |
… | …1001100010100111001 |
3 | 101210211000012221211222 |
4 | 1221102213030110321 |
5 | 3323014104434023 |
6 | 123534204201425 |
7 | 11111416652246 |
oct | 1512247142471 |
9 | 353730187758 |
10 | 113055155513 |
11 | 43a45762723 |
12 | 19ab1b39275 |
13 | a879453331 |
14 | 5686c665cd |
15 | 2e1a433cc8 |
hex | 1a529cc539 |
113055155513 has 2 divisors, whose sum is σ = 113055155514. Its totient is φ = 113055155512.
The previous prime is 113055155503. The next prime is 113055155561. The reversal of 113055155513 is 315551550311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105902732329 + 7152423184 = 325427^2 + 84572^2 .
It is a cyclic number.
It is not a de Polignac number, because 113055155513 - 214 = 113055139129 is a prime.
It is a super-2 number, since 2×1130551555132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113055155503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56527577756 + 56527577757.
It is an arithmetic number, because the mean of its divisors is an integer number (56527577757).
Almost surely, 2113055155513 is an apocalyptic number.
It is an amenable number.
113055155513 is a deficient number, since it is larger than the sum of its proper divisors (1).
113055155513 is an equidigital number, since it uses as much as digits as its factorization.
113055155513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28125, while the sum is 35.
The spelling of 113055155513 in words is "one hundred thirteen billion, fifty-five million, one hundred fifty-five thousand, five hundred thirteen".
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