Base | Representation |
---|---|
bin | 110100101001010011… |
… | …1001110000001000001 |
3 | 101210211000020022100021 |
4 | 1221102213032001001 |
5 | 3323014110144213 |
6 | 123534204253441 |
7 | 11111420011363 |
oct | 1512247160101 |
9 | 353730208307 |
10 | 113055162433 |
11 | 43a45767944 |
12 | 19ab1b41281 |
13 | a879456525 |
14 | 5686c68d33 |
15 | 2e1a435d8d |
hex | 1a529ce041 |
113055162433 has 32 divisors (see below), whose sum is σ = 123801696000. Its totient is φ = 102831805440.
The previous prime is 113055162403. The next prime is 113055162439. The reversal of 113055162433 is 334261550311.
It is a cyclic number.
It is not a de Polignac number, because 113055162433 - 217 = 113055031361 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113055162439) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 103057941 + ... + 103059037.
It is an arithmetic number, because the mean of its divisors is an integer number (3868803000).
Almost surely, 2113055162433 is an apocalyptic number.
It is an amenable number.
113055162433 is a deficient number, since it is larger than the sum of its proper divisors (10746533567).
113055162433 is a wasteful number, since it uses less digits than its factorization.
113055162433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2025.
The product of its (nonzero) digits is 32400, while the sum is 34.
The spelling of 113055162433 in words is "one hundred thirteen billion, fifty-five million, one hundred sixty-two thousand, four hundred thirty-three".
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