113055252303143 has 4 divisors (see below), whose sum is σ = 113168647742760. Its totient is φ = 112941856863528.

The previous prime is 113055252303137. The next prime is 113055252303163. The reversal of 113055252303143 is 341303252550311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113055252303143 - 2²² = 113055248108839 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113055252303097 and 113055252303106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113055252303113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56697718313 + ... + 56697720306.

It is an arithmetic number, because the mean of its divisors is an integer number (28292161935690).

Almost surely, 2^{113055252303143} is an apocalyptic number.

113055252303143 is a deficient number, since it is larger than the sum of its proper divisors (113395439617).

113055252303143 is an equidigital number, since it uses as much as digits as its factorization.

113055252303143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113395439616.

The product of its (nonzero) digits is 162000, while the sum is 38.

The spelling of 113055252303143 in words is "one hundred thirteen trillion, fifty-five billion, two hundred fifty-two million, three hundred three thousand, one hundred forty-three".