Base | Representation |
---|---|
bin | 10101000100001001… |
… | …10010110110000111 |
3 | 1002012011001211022020 |
4 | 22202010302312013 |
5 | 141130112203143 |
6 | 5110105134223 |
7 | 550151524155 |
oct | 124204626607 |
9 | 32164054266 |
10 | 11309100423 |
11 | 4883768595 |
12 | 223748a373 |
13 | 10b2c906ca |
14 | 793d723d5 |
15 | 462c99883 |
hex | 2a2132d87 |
11309100423 has 4 divisors (see below), whose sum is σ = 15078800568. Its totient is φ = 7539400280.
The previous prime is 11309100401. The next prime is 11309100463. The reversal of 11309100423 is 32400190311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11309100423 - 217 = 11308969351 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11309100393 and 11309100402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11309100463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1884850068 + ... + 1884850073.
It is an arithmetic number, because the mean of its divisors is an integer number (3769700142).
Almost surely, 211309100423 is an apocalyptic number.
11309100423 is a deficient number, since it is larger than the sum of its proper divisors (3769700145).
11309100423 is an equidigital number, since it uses as much as digits as its factorization.
11309100423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3769700144.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 11309100423 its reverse (32400190311), we get a palindrome (43709290734).
The spelling of 11309100423 in words is "eleven billion, three hundred nine million, one hundred thousand, four hundred twenty-three".
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