Base | Representation |
---|---|
bin | 10000011101010100111… |
… | …000101110100000001011 |
3 | 11000010022101002011021010 |
4 | 100131110320232200023 |
5 | 122012242120234111 |
6 | 2223324031015003 |
7 | 144466151046630 |
oct | 20352470564013 |
9 | 4003271064233 |
10 | 1131000555531 |
11 | 3a6722368220 |
12 | 16324196a463 |
13 | 82864543362 |
14 | 3ca52766187 |
15 | 1e64736aaa6 |
hex | 10754e2e80b |
1131000555531 has 64 divisors (see below), whose sum is σ = 2077251526656. Its totient is φ = 528929702400.
The previous prime is 1131000555527. The next prime is 1131000555613. The reversal of 1131000555531 is 1355550001311.
It is not a de Polignac number, because 1131000555531 - 22 = 1131000555527 is a prime.
It is a super-2 number, since 2×11310005555312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1131000555431) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6170685 + ... + 6351326.
It is an arithmetic number, because the mean of its divisors is an integer number (32457055104).
Almost surely, 21131000555531 is an apocalyptic number.
1131000555531 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1131000555531 is a deficient number, since it is larger than the sum of its proper divisors (946250971125).
1131000555531 is a wasteful number, since it uses less digits than its factorization.
1131000555531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12522072.
The product of its (nonzero) digits is 5625, while the sum is 30.
Adding to 1131000555531 its reverse (1355550001311), we get a palindrome (2486550556842).
The spelling of 1131000555531 in words is "one trillion, one hundred thirty-one billion, five hundred fifty-five thousand, five hundred thirty-one".
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