Search a number
-
+
113100111213120 = 26325474016013467
BaseRepresentation
bin11001101101110100101011…
…111100111111001001000000
3112211110021011012201121112100
4121231310223330333021000
5104311013011432304440
61040313250202030400
732552133122165643
oct3155645374771100
9484407135647470
10113100111213120
11330455402a2039
12108276864a8400
134b153aa67c375
141dd0108967a5a
15d11ed7d0d230
hex66dd2bf3f240

113100111213120 has 672 divisors, whose sum is σ = 399062752897536. Its totient is φ = 29387243520000.

The previous prime is 113100111213109. The next prime is 113100111213137. The reversal of 113100111213120 is 21312111001311.

113100111213120 is a `hidden beast` number, since 11 + 310 + 0 + 1 + 11 + 21 + 312 + 0 = 666.

It is a super-2 number, since 2×1131001112131202 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 113100111213093 and 113100111213102.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 32621893627 + ... + 32621897093.

It is an arithmetic number, because the mean of its divisors is an integer number (593843382288).

Almost surely, 2113100111213120 is an apocalyptic number.

113100111213120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113100111213120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (199531376448768).

113100111213120 is an abundant number, since it is smaller than the sum of its proper divisors (285962641684416).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113100111213120 is a wasteful number, since it uses less digits than its factorization.

113100111213120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4539 (or 4526 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 18.

Adding to 113100111213120 its reverse (21312111001311), we get a palindrome (134412222214431).

The spelling of 113100111213120 in words is "one hundred thirteen trillion, one hundred billion, one hundred eleven million, two hundred thirteen thousand, one hundred twenty".