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1131001199969 is a prime number
BaseRepresentation
bin10000011101010100111…
…011001011110101100001
311000010022102021220021012
4100131110323023311201
5122012242301344334
62223324052510305
7144466156402514
oct20352473136541
94003272256235
101131001199969
113a6722768413
1216324201b395
138286470a794
143ca52892d7b
151e6474469ce
hex10754ecbd61

1131001199969 has 2 divisors, whose sum is σ = 1131001199970. Its totient is φ = 1131001199968.

The previous prime is 1131001199959. The next prime is 1131001200041. The reversal of 1131001199969 is 9699911001311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 660318760000 + 470682439969 = 812600^2 + 686063^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131001199969 - 24 = 1131001199953 is a prime.

It is a super-2 number, since 2×11310011999692 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1131001199929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565500599984 + 565500599985.

It is an arithmetic number, because the mean of its divisors is an integer number (565500599985).

Almost surely, 21131001199969 is an apocalyptic number.

It is an amenable number.

1131001199969 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131001199969 is an equidigital number, since it uses as much as digits as its factorization.

1131001199969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 118098, while the sum is 50.

The spelling of 1131001199969 in words is "one trillion, one hundred thirty-one billion, one million, one hundred ninety-nine thousand, nine hundred sixty-nine".