Base | Representation |
---|---|
bin | 10000011101010100111… |
… | …110010010001010100001 |
3 | 11000010022110211011121022 |
4 | 100131110332102022201 |
5 | 122012243003343241 |
6 | 2223324122135225 |
7 | 144466166325056 |
oct | 20352476221241 |
9 | 4003273734538 |
10 | 1131002012321 |
11 | 3a6723172785 |
12 | 163242351515 |
13 | 8286493346c |
14 | 3ca52a2502d |
15 | 1e64755754b |
hex | 10754f922a1 |
1131002012321 has 2 divisors, whose sum is σ = 1131002012322. Its totient is φ = 1131002012320.
The previous prime is 1131002012303. The next prime is 1131002012389. The reversal of 1131002012321 is 1232102001311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 832300413025 + 298701599296 = 912305^2 + 546536^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131002012321 - 222 = 1130997818017 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1131002012321.
It is not a weakly prime, because it can be changed into another prime (1131002612321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565501006160 + 565501006161.
It is an arithmetic number, because the mean of its divisors is an integer number (565501006161).
Almost surely, 21131002012321 is an apocalyptic number.
It is an amenable number.
1131002012321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131002012321 is an equidigital number, since it uses as much as digits as its factorization.
1131002012321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1131002012321 its reverse (1232102001311), we get a palindrome (2363104013632).
The spelling of 1131002012321 in words is "one trillion, one hundred thirty-one billion, two million, twelve thousand, three hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •