1131002025 has 24 divisors (see below), whose sum is σ = 1875936480. Its totient is φ = 601261440.

The previous prime is 1131002011. The next prime is 1131002063. The reversal of 1131002025 is 5202001311.

It is not a de Polignac number, because 1131002025 - 2¹¹ = 1130999977 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1131001995 and 1131002013.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 615 + ... + 47564.

It is an arithmetic number, because the mean of its divisors is an integer number (78164020).

Almost surely, 2^1131002025 is an apocalyptic number.

1131002025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1131002025 is a deficient number, since it is larger than the sum of its proper divisors (744934455).

1131002025 is a wasteful number, since it uses less digits than its factorization.

1131002025 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48505 (or 48500 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 1131002025 is about 33630.3735483268. The cubic root of 1131002025 is about 1041.8882193989. Note that the first 3 decimals are identical.

Adding to 1131002025 its reverse (5202001311), we get a palindrome (6333003336).

The spelling of 1131002025 in words is "one billion, one hundred thirty-one million, two thousand, twenty-five".