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11310103033 is a prime number
BaseRepresentation
bin10101000100010001…
…00111100111111001
31002012012221202121221
422202020213213321
5141130341244113
65110142432041
7550163201215
oct124210474771
932165852557
1011310103033
114884292899
122237892621
1310b3251b78
14794153945
15462de698d
hex2a22279f9

11310103033 has 2 divisors, whose sum is σ = 11310103034. Its totient is φ = 11310103032.

The previous prime is 11310102977. The next prime is 11310103067. The reversal of 11310103033 is 33030101311.

11310103033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10492314624 + 817788409 = 102432^2 + 28597^2 .

It is a cyclic number.

It is not a de Polignac number, because 11310103033 - 213 = 11310094841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11310102998 and 11310103016.

It is not a weakly prime, because it can be changed into another prime (11310103433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655051516 + 5655051517.

It is an arithmetic number, because the mean of its divisors is an integer number (5655051517).

Almost surely, 211310103033 is an apocalyptic number.

It is an amenable number.

11310103033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310103033 is an equidigital number, since it uses as much as digits as its factorization.

11310103033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 11310103033 its reverse (33030101311), we get a palindrome (44340204344).

The spelling of 11310103033 in words is "eleven billion, three hundred ten million, one hundred three thousand, thirty-three".