11310113103130 has 8 divisors (see below), whose sum is σ = 20358203585652. Its totient is φ = 4524045241248.

The previous prime is 11310113103101. The next prime is 11310113103217. The reversal of 11310113103130 is 3130131101311.

It can be written as a sum of positive squares in 2 ways, for example, as 9287969378689 + 2022143724441 = 3047617^2 + 1422021^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11310113103098 and 11310113103107.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 565505655147 + ... + 565505655166.

Almost surely, 2^{11310113103130} is an apocalyptic number.

11310113103130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11310113103130 is a deficient number, since it is larger than the sum of its proper divisors (9048090482522).

11310113103130 is a wasteful number, since it uses less digits than its factorization.

11310113103130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1131011310320.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 11310113103130 its reverse (3130131101311), we get a palindrome (14440244204441).

The spelling of 11310113103130 in words is "eleven trillion, three hundred ten billion, one hundred thirteen million, one hundred three thousand, one hundred thirty".