1131011313132 has 24 divisors (see below), whose sum is σ = 2730027308400. Its totient is φ = 364003640896.

The previous prime is 1131011313127. The next prime is 1131011313169. The reversal of 1131011313132 is 2313131101311.

It is a super-3 number, since 3×1131011313132³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131011313099 and 1131011313108.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1625015907 + ... + 1625016602.

It is an arithmetic number, because the mean of its divisors is an integer number (113751137850).

Almost surely, 2^{1131011313132} is an apocalyptic number.

1131011313132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1131011313132 is an abundant number, since it is smaller than the sum of its proper divisors (1599015995268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131011313132 is a wasteful number, since it uses less digits than its factorization.

1131011313132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3250032545 (or 3250032543 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 1131011313132 its reverse (2313131101311), we get a palindrome (3444142414443).

The spelling of 1131011313132 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred thirteen thousand, one hundred thirty-two".