Base | Representation |
---|---|
bin | 10000011101010101100… |
… | …001110000110111101110 |
3 | 11000010100010022200220212 |
4 | 100131111201300313232 |
5 | 122012302344010014 |
6 | 2223325053342422 |
7 | 144466341353123 |
oct | 20352541606756 |
9 | 4003303280825 |
10 | 1131011313134 |
11 | 3a67284455aa |
12 | 163245497a12 |
13 | 8286683b9c1 |
14 | 3ca53d6674a |
15 | 1e64829323e |
hex | 10755870dee |
1131011313134 has 4 divisors (see below), whose sum is σ = 1696516969704. Its totient is φ = 565505656566.
The previous prime is 1131011313127. The next prime is 1131011313169. The reversal of 1131011313134 is 4313131101311.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282752828282 + ... + 282752828285.
It is an arithmetic number, because the mean of its divisors is an integer number (424129242426).
Almost surely, 21131011313134 is an apocalyptic number.
1131011313134 is a deficient number, since it is larger than the sum of its proper divisors (565505656570).
1131011313134 is an equidigital number, since it uses as much as digits as its factorization.
1131011313134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 565505656569.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 1131011313134 its reverse (4313131101311), we get a palindrome (5444142414445).
The spelling of 1131011313134 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred thirteen thousand, one hundred thirty-four".
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