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1131011332000 = 255311101307829
BaseRepresentation
bin10000011101010101100…
…001110101011110100000
311000010100010100122210121
4100131111201311132200
5122012302400111000
62223325054010024
7144466341462124
oct20352541653640
94003303318717
101131011332000
113a67284587a0
121632454a6914
1382866847474
143ca53d6d584
151e648298b1a
hex107558757a0

1131011332000 has 384 divisors, whose sum is σ = 3075214222080. Its totient is φ = 405388800000.

The previous prime is 1131011331977. The next prime is 1131011332049. The reversal of 1131011332000 is 2331101311.

It is a super-3 number, since 3×11310113320003 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1364307586 + ... + 1364308414.

It is an arithmetic number, because the mean of its divisors is an integer number (8008370370).

Almost surely, 21131011332000 is an apocalyptic number.

1131011332000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1131011332000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1537607111040).

1131011332000 is an abundant number, since it is smaller than the sum of its proper divisors (1944202890080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131011332000 is a wasteful number, since it uses less digits than its factorization.

1131011332000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1273 (or 1255 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1131011332000 its reverse (2331101311), we get a palindrome (1133342433311).

The spelling of 1131011332000 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred thirty-two thousand".