Base | Representation |
---|---|
bin | 10000011101010101100… |
… | …001110101100000001111 |
3 | 11000010100010100122221201 |
4 | 100131111201311200033 |
5 | 122012302400111421 |
6 | 2223325054010331 |
7 | 144466341462343 |
oct | 20352541654017 |
9 | 4003303318851 |
10 | 1131011332111 |
11 | 3a6728458891 |
12 | 1632454a69a7 |
13 | 8286684752b |
14 | 3ca53d6d623 |
15 | 1e648298b91 |
hex | 1075587580f |
1131011332111 has 4 divisors (see below), whose sum is σ = 1131032544552. Its totient is φ = 1130990119672.
The previous prime is 1131011332093. The next prime is 1131011332193. The reversal of 1131011332111 is 1112331101311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1131011332111 - 221 = 1131009234959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131011332811) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10526041 + ... + 10632946.
It is an arithmetic number, because the mean of its divisors is an integer number (282758136138).
Almost surely, 21131011332111 is an apocalyptic number.
1131011332111 is a deficient number, since it is larger than the sum of its proper divisors (21212441).
1131011332111 is an equidigital number, since it uses as much as digits as its factorization.
1131011332111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21212440.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 1131011332111 its reverse (1112331101311), we get a palindrome (2243342433422).
The spelling of 1131011332111 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred thirty-two thousand, one hundred eleven".
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