Base | Representation |
---|---|
bin | 10000011101010101100… |
… | …001110101100001100001 |
3 | 11000010100010100200001202 |
4 | 100131111201311201201 |
5 | 122012302400112233 |
6 | 2223325054010545 |
7 | 144466341462521 |
oct | 20352541654141 |
9 | 4003303320052 |
10 | 1131011332193 |
11 | 3a6728458956 |
12 | 1632454a6a55 |
13 | 82866847592 |
14 | 3ca53d6d681 |
15 | 1e648298be8 |
hex | 10755875861 |
1131011332193 has 2 divisors, whose sum is σ = 1131011332194. Its totient is φ = 1131011332192.
The previous prime is 1131011332093. The next prime is 1131011332201. The reversal of 1131011332193 is 3912331101311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1028212224064 + 102799108129 = 1014008^2 + 320623^2 .
It is an emirp because it is prime and its reverse (3912331101311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1131011332193 - 222 = 1131007137889 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131011332093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565505666096 + 565505666097.
It is an arithmetic number, because the mean of its divisors is an integer number (565505666097).
Almost surely, 21131011332193 is an apocalyptic number.
It is an amenable number.
1131011332193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131011332193 is an equidigital number, since it uses as much as digits as its factorization.
1131011332193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 29.
The spelling of 1131011332193 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred thirty-two thousand, one hundred ninety-three".
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