1131013002113 has 2 divisors, whose sum is σ = 1131013002114. Its totient is φ = 1131013002112.

The previous prime is 1131013002101. The next prime is 1131013002131. The reversal of 1131013002113 is 3112003101311.

Together with next prime (1131013002131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 581601466384 + 549411535729 = 762628^2 + 741223^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131013002113 - 2³² = 1126718034817 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131013002091 and 1131013002100.

It is not a weakly prime, because it can be changed into another prime (1131013002193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565506501056 + 565506501057.

It is an arithmetic number, because the mean of its divisors is an integer number (565506501057).

Almost surely, 2^{1131013002113} is an apocalyptic number.

It is an amenable number.

1131013002113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131013002113 is an equidigital number, since it uses as much as digits as its factorization.

1131013002113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1131013002113 its reverse (3112003101311), we get a palindrome (4243016103424).

The spelling of 1131013002113 in words is "one trillion, one hundred thirty-one billion, thirteen million, two thousand, one hundred thirteen".