11310130033 has 2 divisors, whose sum is σ = 11310130034. Its totient is φ = 11310130032.

The previous prime is 11310129991. The next prime is 11310130043. The reversal of 11310130033 is 33003101311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8472650209 + 2837479824 = 92047^2 + 53268^2 .

It is an emirp because it is prime and its reverse (33003101311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11310130033 - 2²⁹ = 10773259121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11310129989 and 11310130016.

It is not a weakly prime, because it can be changed into another prime (11310130043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655065016 + 5655065017.

It is an arithmetic number, because the mean of its divisors is an integer number (5655065017).

Almost surely, 2^11310130033 is an apocalyptic number.

It is an amenable number.

11310130033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310130033 is an equidigital number, since it uses as much as digits as its factorization.

11310130033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 11310130033 its reverse (33003101311), we get a palindrome (44313231344).

The spelling of 11310130033 in words is "eleven billion, three hundred ten million, one hundred thirty thousand, thirty-three".