1131013441 has 2 divisors, whose sum is σ = 1131013442. Its totient is φ = 1131013440.

The previous prime is 1131013409. The next prime is 1131013463. The reversal of 1131013441 is 1443101311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 648771841 + 482241600 = 25471^2 + 21960^2 .

It is an emirp because it is prime and its reverse (1443101311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131013441 - 2⁵ = 1131013409 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131014441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565506720 + 565506721.

It is an arithmetic number, because the mean of its divisors is an integer number (565506721).

Almost surely, 2^1131013441 is an apocalyptic number.

It is an amenable number.

1131013441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131013441 is an equidigital number, since it uses as much as digits as its factorization.

1131013441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1131013441 is about 33630.5432754215. The cubic root of 1131013441 is about 1041.8917248910.

Adding to 1131013441 its reverse (1443101311), we get a palindrome (2574114752).

The spelling of 1131013441 in words is "one billion, one hundred thirty-one million, thirteen thousand, four hundred forty-one".