1131014010403 has 2 divisors, whose sum is σ = 1131014010404. Its totient is φ = 1131014010402.

The previous prime is 1131014010389. The next prime is 1131014010431. The reversal of 1131014010403 is 3040104101311.

It is a weak prime.

It is an emirp because it is prime and its reverse (3040104101311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131014010403 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131014110403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565507005201 + 565507005202.

It is an arithmetic number, because the mean of its divisors is an integer number (565507005202).

Almost surely, 2^{1131014010403} is an apocalyptic number.

1131014010403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131014010403 is an equidigital number, since it uses as much as digits as its factorization.

1131014010403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1131014010403 its reverse (3040104101311), we get a palindrome (4171118111714).

The spelling of 1131014010403 in words is "one trillion, one hundred thirty-one billion, fourteen million, ten thousand, four hundred three".