Base | Representation |
---|---|
bin | 10000011101010110000… |
… | …011110001110111101001 |
3 | 11000010100202002201201122 |
4 | 100131112003301313221 |
5 | 122012312134330441 |
6 | 2223330012425025 |
7 | 144466510222145 |
oct | 20352603616751 |
9 | 4003322081648 |
10 | 1131020230121 |
11 | 3a6732486011 |
12 | 163248478175 |
13 | 82868641622 |
14 | 3ca55208225 |
15 | 1e648e5534b |
hex | 107560f1de9 |
1131020230121 has 2 divisors, whose sum is σ = 1131020230122. Its totient is φ = 1131020230120.
The previous prime is 1131020230103. The next prime is 1131020230133. The reversal of 1131020230121 is 1210320201311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 982945342096 + 148074888025 = 991436^2 + 384805^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131020230121 - 214 = 1131020213737 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1131020230121.
It is not a weakly prime, because it can be changed into another prime (1131020250121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565510115060 + 565510115061.
It is an arithmetic number, because the mean of its divisors is an integer number (565510115061).
Almost surely, 21131020230121 is an apocalyptic number.
It is an amenable number.
1131020230121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131020230121 is an equidigital number, since it uses as much as digits as its factorization.
1131020230121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1131020230121 its reverse (1210320201311), we get a palindrome (2341340431432).
The spelling of 1131020230121 in words is "one trillion, one hundred thirty-one billion, twenty million, two hundred thirty thousand, one hundred twenty-one".
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