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11310210121307 is a prime number
BaseRepresentation
bin1010010010010101110100…
…0011100111111001011011
31111001020121222201121102112
42210211131003213321123
52440301302242340212
640015501103022535
72245064356541336
oct244453503477133
944036558647375
1011310210121307
1136706a6836499
121327bb259aa4b
1364071862c256
142b15ba6d561d
151493103ce422
hexa495d0e7e5b

11310210121307 has 2 divisors, whose sum is σ = 11310210121308. Its totient is φ = 11310210121306.

The previous prime is 11310210121283. The next prime is 11310210121319. The reversal of 11310210121307 is 70312101201311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11310210121307 - 232 = 11305915154011 is a prime.

It is not a weakly prime, because it can be changed into another prime (11310210121367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655105060653 + 5655105060654.

It is an arithmetic number, because the mean of its divisors is an integer number (5655105060654).

Almost surely, 211310210121307 is an apocalyptic number.

11310210121307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310210121307 is an equidigital number, since it uses as much as digits as its factorization.

11310210121307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 11310210121307 its reverse (70312101201311), we get a palindrome (81622311322618).

The spelling of 11310210121307 in words is "eleven trillion, three hundred ten billion, two hundred ten million, one hundred twenty-one thousand, three hundred seven".