113102311031223 has 4 divisors (see below), whose sum is σ = 150803081374968. Its totient is φ = 75401540687480.

The previous prime is 113102311031191. The next prime is 113102311031329. The reversal of 113102311031223 is 322130113201311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113102311031223 - 2⁵ = 113102311031191 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113102311031193 and 113102311031202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113102311031023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18850385171868 + ... + 18850385171873.

It is an arithmetic number, because the mean of its divisors is an integer number (37700770343742).

Almost surely, 2^{113102311031223} is an apocalyptic number.

113102311031223 is a deficient number, since it is larger than the sum of its proper divisors (37700770343745).

113102311031223 is an equidigital number, since it uses as much as digits as its factorization.

113102311031223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37700770343744.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 113102311031223 its reverse (322130113201311), we get a palindrome (435232424232534).

The spelling of 113102311031223 in words is "one hundred thirteen trillion, one hundred two billion, three hundred eleven million, thirty-one thousand, two hundred twenty-three".