Base | Representation |
---|---|
bin | 110100101010101101… |
… | …1000111000111111001 |
3 | 101210221021222011112022 |
4 | 1221111123013013321 |
5 | 3323113143220441 |
6 | 123543011124225 |
7 | 11112531600350 |
oct | 1512533070771 |
9 | 353837864468 |
10 | 113102320121 |
11 | 43a6a34713a |
12 | 19b058a3675 |
13 | a886157c9b |
14 | 568d222997 |
15 | 2e1e64d84b |
hex | 1a556c71f9 |
113102320121 has 16 divisors (see below), whose sum is σ = 132047185920. Its totient is φ = 94855464720.
The previous prime is 113102320073. The next prime is 113102320141. The reversal of 113102320121 is 121023201311.
It is a cyclic number.
It is not a de Polignac number, because 113102320121 - 210 = 113102319097 is a prime.
It is a super-2 number, since 2×1131023201212 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 113102320121.
It is not an unprimeable number, because it can be changed into a prime (113102320141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1167770 + ... + 1260908.
It is an arithmetic number, because the mean of its divisors is an integer number (8252949120).
Almost surely, 2113102320121 is an apocalyptic number.
It is an amenable number.
113102320121 is a deficient number, since it is larger than the sum of its proper divisors (18944865799).
113102320121 is an equidigital number, since it uses as much as digits as its factorization.
113102320121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96884.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 113102320121 its reverse (121023201311), we get a palindrome (234125521432).
The spelling of 113102320121 in words is "one hundred thirteen billion, one hundred two million, three hundred twenty thousand, one hundred twenty-one".
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