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113102434534 = 256551217267
BaseRepresentation
bin110100101010101101…
…1100011000011100110
3101210221022011222110211
41221111123203003212
53323113210401114
6123543013410034
711112532555045
oct1512533430346
9353838158424
10113102434534
1143a6a4150a1
1219b0593991a
13a88619809b
14568d25255c
152e1e6726c4
hex1a556e30e6

113102434534 has 4 divisors (see below), whose sum is σ = 169653651804. Its totient is φ = 56551217266.

The previous prime is 113102434517. The next prime is 113102434537. The reversal of 113102434534 is 435434201311.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 113102434496 and 113102434505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113102434537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28275608632 + ... + 28275608635.

It is an arithmetic number, because the mean of its divisors is an integer number (42413412951).

Almost surely, 2113102434534 is an apocalyptic number.

113102434534 is a deficient number, since it is larger than the sum of its proper divisors (56551217270).

113102434534 is an equidigital number, since it uses as much as digits as its factorization.

113102434534 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56551217269.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 113102434534 its reverse (435434201311), we get a palindrome (548536635845).

The spelling of 113102434534 in words is "one hundred thirteen billion, one hundred two million, four hundred thirty-four thousand, five hundred thirty-four".

Divisors: 1 2 56551217267 113102434534