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11310310241 is a prime number
BaseRepresentation
bin10101000100010010…
…11010001101100001
31002012020100021212022
422202021122031201
5141130414411431
65110151111225
7550165023266
oct124211321541
932166307768
1011310310241
11488441453a
122237972515
1310b32c5289
147941a926d
15462e3807b
hex2a225a361

11310310241 has 2 divisors, whose sum is σ = 11310310242. Its totient is φ = 11310310240.

The previous prime is 11310310163. The next prime is 11310310279. The reversal of 11310310241 is 14201301311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11256361216 + 53949025 = 106096^2 + 7345^2 .

It is an emirp because it is prime and its reverse (14201301311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11310310241 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11310310541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655155120 + 5655155121.

It is an arithmetic number, because the mean of its divisors is an integer number (5655155121).

Almost surely, 211310310241 is an apocalyptic number.

It is an amenable number.

11310310241 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310310241 is an equidigital number, since it uses as much as digits as its factorization.

11310310241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11310310241 its reverse (14201301311), we get a palindrome (25511611552).

The spelling of 11310310241 in words is "eleven billion, three hundred ten million, three hundred ten thousand, two hundred forty-one".