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113103120032153 is a prime number
BaseRepresentation
bin11001101101110111011111…
…010010101110000110011001
3112211110112220220100110022022
4121231313133102232012121
5104311040142212012103
61040314504523304225
732552300515552046
oct3155673722560631
9484415826313268
10113103120032153
1133046844736339
121082818607b075
134b15769b30a64
141dd03123c81cd
15d12112045138
hex66dddf4ae199

113103120032153 has 2 divisors, whose sum is σ = 113103120032154. Its totient is φ = 113103120032152.

The previous prime is 113103120032129. The next prime is 113103120032191. The reversal of 113103120032153 is 351230021301311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61644921639184 + 51458198392969 = 7851428^2 + 7173437^2 .

It is a cyclic number.

It is not a de Polignac number, because 113103120032153 - 218 = 113103119770009 is a prime.

It is a super-2 number, since 2×1131031200321532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113103120022153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56551560016076 + 56551560016077.

It is an arithmetic number, because the mean of its divisors is an integer number (56551560016077).

Almost surely, 2113103120032153 is an apocalyptic number.

It is an amenable number.

113103120032153 is a deficient number, since it is larger than the sum of its proper divisors (1).

113103120032153 is an equidigital number, since it uses as much as digits as its factorization.

113103120032153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 26.

Adding to 113103120032153 its reverse (351230021301311), we get a palindrome (464333141333464).

The spelling of 113103120032153 in words is "one hundred thirteen trillion, one hundred three billion, one hundred twenty million, thirty-two thousand, one hundred fifty-three".