Base | Representation |
---|---|
bin | 10101000100010010… |
… | …11010111001011011 |
3 | 1002012020100102201101 |
4 | 22202021122321123 |
5 | 141130420004201 |
6 | 5110151132231 |
7 | 550165034422 |
oct | 124211327133 |
9 | 32166312641 |
10 | 11310313051 |
11 | 4884416664 |
12 | 2237974077 |
13 | 10b32c663b |
14 | 7941aa2b9 |
15 | 462e38d01 |
hex | 2a225ae5b |
11310313051 has 2 divisors, whose sum is σ = 11310313052. Its totient is φ = 11310313050.
The previous prime is 11310312967. The next prime is 11310313099. The reversal of 11310313051 is 15031301311.
11310313051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11310313051 - 29 = 11310312539 is a prime.
It is not a weakly prime, because it can be changed into another prime (11310313351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655156525 + 5655156526.
It is an arithmetic number, because the mean of its divisors is an integer number (5655156526).
Almost surely, 211310313051 is an apocalyptic number.
11310313051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310313051 is an equidigital number, since it uses as much as digits as its factorization.
11310313051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 135, while the sum is 19.
Adding to 11310313051 its reverse (15031301311), we get a palindrome (26341614362).
The spelling of 11310313051 in words is "eleven billion, three hundred ten million, three hundred thirteen thousand, fifty-one".
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