Base | Representation |
---|---|
bin | 10000011101010110101… |
… | …110000011001110000001 |
3 | 11000010101111221201011012 |
4 | 100131112232003032001 |
5 | 122012323003424413 |
6 | 2223331050130305 |
7 | 144500003343455 |
oct | 20352656031601 |
9 | 4003344851135 |
10 | 1131031311233 |
11 | 3a673876445a |
12 | 163250120995 |
13 | 8286aa212b5 |
14 | 3ca56890665 |
15 | 1e649de37a8 |
hex | 10756b83381 |
1131031311233 has 2 divisors, whose sum is σ = 1131031311234. Its totient is φ = 1131031311232.
The previous prime is 1131031311227. The next prime is 1131031311349. The reversal of 1131031311233 is 3321131301311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1088917294144 + 42114017089 = 1043512^2 + 205217^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131031311233 - 26 = 1131031311169 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131031311199 and 1131031311208.
It is not a weakly prime, because it can be changed into another prime (1131031311733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565515655616 + 565515655617.
It is an arithmetic number, because the mean of its divisors is an integer number (565515655617).
Almost surely, 21131031311233 is an apocalyptic number.
It is an amenable number.
1131031311233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131031311233 is an equidigital number, since it uses as much as digits as its factorization.
1131031311233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 1131031311233 its reverse (3321131301311), we get a palindrome (4452162612544).
The spelling of 1131031311233 in words is "one trillion, one hundred thirty-one billion, thirty-one million, three hundred eleven thousand, two hundred thirty-three".
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