Base | Representation |
---|---|
bin | 10000011101010110110… |
… | …000101110010101111001 |
3 | 11000010101120021022122012 |
4 | 100131112300232111321 |
5 | 122012323143342103 |
6 | 2223331113135305 |
7 | 144500012323121 |
oct | 20352660562571 |
9 | 4003346238565 |
10 | 1131032012153 |
11 | 3a67390a302a |
12 | 1632503ba535 |
13 | 8286ac08344 |
14 | 3ca569d3c81 |
15 | 1e649ed12d8 |
hex | 10756c2e579 |
1131032012153 has 2 divisors, whose sum is σ = 1131032012154. Its totient is φ = 1131032012152.
The previous prime is 1131032012101. The next prime is 1131032012191. The reversal of 1131032012153 is 3512102301311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1116513449104 + 14518563049 = 1056652^2 + 120493^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131032012153 - 234 = 1113852142969 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1131032012653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565516006076 + 565516006077.
It is an arithmetic number, because the mean of its divisors is an integer number (565516006077).
Almost surely, 21131032012153 is an apocalyptic number.
It is an amenable number.
1131032012153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131032012153 is an equidigital number, since it uses as much as digits as its factorization.
1131032012153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 1131032012153 its reverse (3512102301311), we get a palindrome (4643134313464).
The spelling of 1131032012153 in words is "one trillion, one hundred thirty-one billion, thirty-two million, twelve thousand, one hundred fifty-three".
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