113104051 has 2 divisors, whose sum is σ = 113104052. Its totient is φ = 113104050.

The previous prime is 113104007. The next prime is 113104081. The reversal of 113104051 is 150401311.

It is a strong prime.

It is an emirp because it is prime and its reverse (150401311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113104051 - 2⁹ = 113103539 is a prime.

It is a super-2 number, since 2×113104051² = 25585052705221202, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113104081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56552025 + 56552026.

It is an arithmetic number, because the mean of its divisors is an integer number (56552026).

Almost surely, 2^113104051 is an apocalyptic number.

113104051 is a deficient number, since it is larger than the sum of its proper divisors (1).

113104051 is an equidigital number, since it uses as much as digits as its factorization.

113104051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 113104051 is about 10635.0388339677. The cubic root of 113104051 is about 483.6071576688.

Adding to 113104051 its reverse (150401311), we get a palindrome (263505362).

The spelling of 113104051 in words is "one hundred thirteen million, one hundred four thousand, fifty-one".