11311010031121 has 2 divisors, whose sum is σ = 11311010031122. Its totient is φ = 11311010031120.

The previous prime is 11311010031109. The next prime is 11311010031157. The reversal of 11311010031121 is 12113001011311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7499491790400 + 3811518240721 = 2738520^2 + 1952311^2 .

It is an emirp because it is prime and its reverse (12113001011311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11311010031121 - 2⁵ = 11311010031089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11311010031095 and 11311010031104.

It is not a weakly prime, because it can be changed into another prime (11311010035121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655505015560 + 5655505015561.

It is an arithmetic number, because the mean of its divisors is an integer number (5655505015561).

Almost surely, 2^{11311010031121} is an apocalyptic number.

It is an amenable number.

11311010031121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311010031121 is an equidigital number, since it uses as much as digits as its factorization.

11311010031121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 11311010031121 its reverse (12113001011311), we get a palindrome (23424011042432).

The spelling of 11311010031121 in words is "eleven trillion, three hundred eleven billion, ten million, thirty-one thousand, one hundred twenty-one".