Base | Representation |
---|---|
bin | 1010010010011000110011… |
… | …0111101100010110111111 |
3 | 1111001022200220011112000202 |
4 | 2210212030313230112333 |
5 | 2440304423122101343 |
6 | 40020112440314115 |
7 | 2245123300131356 |
oct | 244461467542677 |
9 | 44038626145022 |
10 | 11311012300223 |
11 | 3670a78625379 |
12 | 132819717293b |
13 | 640815895b2c |
14 | 2b165506a99d |
15 | 14935aa36db8 |
hex | a498cdec5bf |
11311012300223 has 4 divisors (see below), whose sum is σ = 11976365964960. Its totient is φ = 10645658635488.
The previous prime is 11311012300193. The next prime is 11311012300229. The reversal of 11311012300223 is 32200321011311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11311012300223 - 214 = 11311012283839 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11311012300195 and 11311012300204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11311012300229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 332676832343 + ... + 332676832376.
It is an arithmetic number, because the mean of its divisors is an integer number (2994091491240).
Almost surely, 211311012300223 is an apocalyptic number.
11311012300223 is a deficient number, since it is larger than the sum of its proper divisors (665353664737).
11311012300223 is an equidigital number, since it uses as much as digits as its factorization.
11311012300223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 665353664736.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11311012300223 its reverse (32200321011311), we get a palindrome (43511333311534).
The spelling of 11311012300223 in words is "eleven trillion, three hundred eleven billion, twelve million, three hundred thousand, two hundred twenty-three".
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