Base | Representation |
---|---|
bin | 10000011101011010111… |
… | …100111001101010101101 |
3 | 11000010120110112222110012 |
4 | 100131122330321222231 |
5 | 122012444143010013 |
6 | 2223342104023005 |
7 | 144501525012212 |
oct | 20353274715255 |
9 | 4003513488405 |
10 | 1131102313133 |
11 | 3a677484a211 |
12 | 16326ba61a65 |
13 | 8287c650b60 |
14 | 3ca62093b09 |
15 | 1e65126b1a8 |
hex | 1075af39aad |
1131102313133 has 8 divisors (see below), whose sum is σ = 1230668021688. Its totient is φ = 1033330581504.
The previous prime is 1131102313123. The next prime is 1131102313139. The reversal of 1131102313133 is 3313132011311.
It can be written as a sum of positive squares in 4 ways, for example, as 163865468809 + 967236844324 = 404803^2 + 983482^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1131102313133 - 28 = 1131102312877 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1131102313099 and 1131102313108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131102313139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 448492916 + ... + 448495437.
It is an arithmetic number, because the mean of its divisors is an integer number (153833502711).
Almost surely, 21131102313133 is an apocalyptic number.
1131102313133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1131102313133 is a deficient number, since it is larger than the sum of its proper divisors (99565708555).
1131102313133 is an equidigital number, since it uses as much as digits as its factorization.
1131102313133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 896988463.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 1131102313133 its reverse (3313132011311), we get a palindrome (4444234324444).
The spelling of 1131102313133 in words is "one trillion, one hundred thirty-one billion, one hundred two million, three hundred thirteen thousand, one hundred thirty-three".
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