Base | Representation |
---|---|
bin | 11001101101111110001011… |
… | …010000111001010000101111 |
3 | 112211111020110022002212201000 |
4 | 121231332023100321100233 |
5 | 104311144343322431111 |
6 | 1040322053215251343 |
7 | 32552643453154656 |
oct | 3155761320712057 |
9 | 484436408085630 |
10 | 113110300202031 |
11 | 33049899759230 |
12 | 1082964a819b53 |
13 | 4b16342569ca2 |
14 | 1dd07d3c4419d |
15 | d123d259cc56 |
hex | 66df8b43942f |
113110300202031 has 64 divisors (see below), whose sum is σ = 183062170368000. Its totient is φ = 68455101075840.
The previous prime is 113110300202027. The next prime is 113110300202069. The reversal of 113110300202031 is 130202003011311.
113110300202031 is a `hidden beast` number, since 1 + 1 + 311 + 0 + 300 + 2 + 0 + 20 + 31 = 666.
It is not a de Polignac number, because 113110300202031 - 22 = 113110300202027 is a prime.
It is a super-2 number, since 2×1131103002020312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113110300201995 and 113110300202013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113110300207031) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2442489105 + ... + 2442535413.
It is an arithmetic number, because the mean of its divisors is an integer number (2860346412000).
Almost surely, 2113110300202031 is an apocalyptic number.
113110300202031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
113110300202031 is a deficient number, since it is larger than the sum of its proper divisors (69951870165969).
113110300202031 is a wasteful number, since it uses less digits than its factorization.
113110300202031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57741 (or 57735 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 113110300202031 its reverse (130202003011311), we get a palindrome (243312303213342).
The spelling of 113110300202031 in words is "one hundred thirteen trillion, one hundred ten billion, three hundred million, two hundred two thousand, thirty-one".
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