Base | Representation |
---|---|
bin | 1010010010011000111000… |
… | …1000010011111111100011 |
3 | 1111001022202100221020020022 |
4 | 2210212032020103333203 |
5 | 2440304444024342313 |
6 | 40020114513304055 |
7 | 2245123644562205 |
oct | 244461610237743 |
9 | 44038670836208 |
10 | 11311033434083 |
11 | 3670a8954a579 |
12 | 13281a226502b |
13 | 64081a085386 |
14 | 2b1657bac775 |
15 | 14935c80dc08 |
hex | a498e213fe3 |
11311033434083 has 2 divisors, whose sum is σ = 11311033434084. Its totient is φ = 11311033434082.
The previous prime is 11311033434061. The next prime is 11311033434109. The reversal of 11311033434083 is 38043433011311.
11311033434083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11311033434083 - 214 = 11311033417699 is a prime.
It is not a weakly prime, because it can be changed into another prime (11311033434023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655516717041 + 5655516717042.
It is an arithmetic number, because the mean of its divisors is an integer number (5655516717042).
Almost surely, 211311033434083 is an apocalyptic number.
11311033434083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311033434083 is an equidigital number, since it uses as much as digits as its factorization.
11311033434083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 35.
Adding to 11311033434083 its reverse (38043433011311), we get a palindrome (49354466445394).
The spelling of 11311033434083 in words is "eleven trillion, three hundred eleven billion, thirty-three million, four hundred thirty-four thousand, eighty-three".
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