Base | Representation |
---|---|
bin | 1010010010011001001011… |
… | …0000101010110101111011 |
3 | 1111001022221210010012102122 |
4 | 2210212102300222311323 |
5 | 2440310123421403144 |
6 | 40020130330351455 |
7 | 2245125610116362 |
oct | 244462260526573 |
9 | 44038853105378 |
10 | 11311111122299 |
11 | 367101939190a |
12 | 132820428b58b |
13 | 6408301b6431 |
14 | 2b16642327d9 |
15 | 1493645577ee |
hex | a4992c2ad7b |
11311111122299 has 2 divisors, whose sum is σ = 11311111122300. Its totient is φ = 11311111122298.
The previous prime is 11311111122293. The next prime is 11311111122307. The reversal of 11311111122299 is 99222111111311.
11311111122299 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11311111122299 - 28 = 11311111122043 is a prime.
It is a super-2 number, since 2×113111111222992 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11311111122293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655555561149 + 5655555561150.
It is an arithmetic number, because the mean of its divisors is an integer number (5655555561150).
Almost surely, 211311111122299 is an apocalyptic number.
11311111122299 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311111122299 is an equidigital number, since it uses as much as digits as its factorization.
11311111122299 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1944, while the sum is 35.
The spelling of 11311111122299 in words is "eleven trillion, three hundred eleven billion, one hundred eleven million, one hundred twenty-two thousand, two hundred ninety-nine".
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