Base | Representation |
---|---|
bin | 11001101101111111000001… |
… | …101011000001100001101011 |
3 | 112211111022210220201220022202 |
4 | 121231333001223001201223 |
5 | 104311203231013140131 |
6 | 1040322323544210415 |
7 | 32553005206044422 |
oct | 3155770153014153 |
9 | 484438726656282 |
10 | 113111213021291 |
11 | 3304a217a46911 |
12 | 10829864469a0b |
13 | 4b16459701524 |
14 | 1dd087d17a2b9 |
15 | d124377acbcb |
hex | 66dfc1ac186b |
113111213021291 has 2 divisors, whose sum is σ = 113111213021292. Its totient is φ = 113111213021290.
The previous prime is 113111213021159. The next prime is 113111213021351. The reversal of 113111213021291 is 192120312111311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113111213021291 - 218 = 113111212759147 is a prime.
It is a super-2 number, since 2×1131112130212912 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113111210021291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555606510645 + 56555606510646.
It is an arithmetic number, because the mean of its divisors is an integer number (56555606510646).
Almost surely, 2113111213021291 is an apocalyptic number.
113111213021291 is a deficient number, since it is larger than the sum of its proper divisors (1).
113111213021291 is an equidigital number, since it uses as much as digits as its factorization.
113111213021291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 29.
The spelling of 113111213021291 in words is "one hundred thirteen trillion, one hundred eleven billion, two hundred thirteen million, twenty-one thousand, two hundred ninety-one".
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