11311130131331 has 2 divisors, whose sum is σ = 11311130131332. Its totient is φ = 11311130131330.

The previous prime is 11311130131313. The next prime is 11311130131391. The reversal of 11311130131331 is 13313103111311.

11311130131331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (11311130131313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11311130131331 - 2¹⁸ = 11311129869187 is a prime.

It is a super-2 number, since 2×11311130131331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11311130131297 and 11311130131306.

It is not a weakly prime, because it can be changed into another prime (11311130131391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655565065665 + 5655565065666.

It is an arithmetic number, because the mean of its divisors is an integer number (5655565065666).

Almost surely, 2^{11311130131331} is an apocalyptic number.

11311130131331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311130131331 is an equidigital number, since it uses as much as digits as its factorization.

11311130131331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 23.

Adding to 11311130131331 its reverse (13313103111311), we get a palindrome (24624233242642).

The spelling of 11311130131331 in words is "eleven trillion, three hundred eleven billion, one hundred thirty million, one hundred thirty-one thousand, three hundred thirty-one".