Base | Representation |
---|---|
bin | 110100101010111110… |
… | …1011010011010110011 |
3 | 101210221220220000010202 |
4 | 1221111331122122303 |
5 | 3323122443441201 |
6 | 123543531545415 |
7 | 11113001201033 |
oct | 1512575323263 |
9 | 353856800122 |
10 | 113111312051 |
11 | 43a74428991 |
12 | 19b088bb26b |
13 | a887c85a5a |
14 | 56904c38c3 |
15 | 2e20327c6b |
hex | 1a55f5a6b3 |
113111312051 has 2 divisors, whose sum is σ = 113111312052. Its totient is φ = 113111312050.
The previous prime is 113111312021. The next prime is 113111312063. The reversal of 113111312051 is 150213111311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113111312051 - 26 = 113111311987 is a prime.
It is not a weakly prime, because it can be changed into another prime (113111312011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555656025 + 56555656026.
It is an arithmetic number, because the mean of its divisors is an integer number (56555656026).
Almost surely, 2113111312051 is an apocalyptic number.
113111312051 is a deficient number, since it is larger than the sum of its proper divisors (1).
113111312051 is an equidigital number, since it uses as much as digits as its factorization.
113111312051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 20.
Adding to 113111312051 its reverse (150213111311), we get a palindrome (263324423362).
The spelling of 113111312051 in words is "one hundred thirteen billion, one hundred eleven million, three hundred twelve thousand, fifty-one".
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