Search a number
-
+
113111512433 is a prime number
BaseRepresentation
bin110100101010111111…
…0001011010101110001
3101210221221021012000022
41221111332023111301
53323123021344213
6123543540133225
711113002664163
oct1512576132561
9353857235008
10113111512433
1143a74555497
1219b08997215
13a88802601a
145690536933
152e20367308
hex1a55f8b571

113111512433 has 2 divisors, whose sum is σ = 113111512434. Its totient is φ = 113111512432.

The previous prime is 113111512379. The next prime is 113111512439. The reversal of 113111512433 is 334215111311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102984511744 + 10127000689 = 320912^2 + 100633^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113111512433 is a prime.

It is not a weakly prime, because it can be changed into another prime (113111512439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555756216 + 56555756217.

It is an arithmetic number, because the mean of its divisors is an integer number (56555756217).

Almost surely, 2113111512433 is an apocalyptic number.

It is an amenable number.

113111512433 is a deficient number, since it is larger than the sum of its proper divisors (1).

113111512433 is an equidigital number, since it uses as much as digits as its factorization.

113111512433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1080, while the sum is 26.

Adding to 113111512433 its reverse (334215111311), we get a palindrome (447326623744).

The spelling of 113111512433 in words is "one hundred thirteen billion, one hundred eleven million, five hundred twelve thousand, four hundred thirty-three".