11311155344033 has 2 divisors, whose sum is σ = 11311155344034. Its totient is φ = 11311155344032.

The previous prime is 11311155343933. The next prime is 11311155344051. The reversal of 11311155344033 is 33044355111311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8916482658304 + 2394672685729 = 2986048^2 + 1547473^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11311155344033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11311155343984 and 11311155344002.

It is not a weakly prime, because it can be changed into another prime (11311155344053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655577672016 + 5655577672017.

It is an arithmetic number, because the mean of its divisors is an integer number (5655577672017).

Almost surely, 2^{11311155344033} is an apocalyptic number.

It is an amenable number.

11311155344033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311155344033 is an equidigital number, since it uses as much as digits as its factorization.

11311155344033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 35.

The spelling of 11311155344033 in words is "eleven trillion, three hundred eleven billion, one hundred fifty-five million, three hundred forty-four thousand, thirty-three".