Base | Representation |
---|---|
bin | 11001101101111111110001… |
… | …010100000011011100101001 |
3 | 112211111101212121201210010011 |
4 | 121231333301110003130221 |
5 | 104311211400122244332 |
6 | 1040322535135451521 |
7 | 32553034052622241 |
oct | 3155776124033451 |
9 | 484441777653104 |
10 | 113112012306217 |
11 | 3304a598139471 |
12 | 10829a48086ba1 |
13 | 4b16556193aa2 |
14 | 1dd091739ab21 |
15 | d12482a42e47 |
hex | 66dff1503729 |
113112012306217 has 2 divisors, whose sum is σ = 113112012306218. Its totient is φ = 113112012306216.
The previous prime is 113112012306199. The next prime is 113112012306289. The reversal of 113112012306217 is 712603210211311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84325578946816 + 28786433359401 = 9182896^2 + 5365299^2 .
It is a cyclic number.
It is not a de Polignac number, because 113112012306217 - 219 = 113112011781929 is a prime.
It is not a weakly prime, because it can be changed into another prime (113112012346217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556006153108 + 56556006153109.
It is an arithmetic number, because the mean of its divisors is an integer number (56556006153109).
Almost surely, 2113112012306217 is an apocalyptic number.
It is an amenable number.
113112012306217 is a deficient number, since it is larger than the sum of its proper divisors (1).
113112012306217 is an equidigital number, since it uses as much as digits as its factorization.
113112012306217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 31.
Adding to 113112012306217 its reverse (712603210211311), we get a palindrome (825715222517528).
The spelling of 113112012306217 in words is "one hundred thirteen trillion, one hundred twelve billion, twelve million, three hundred six thousand, two hundred seventeen".
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